WebAnswer (1 of 2): Consider the more generalised form of the function (for g(x)>0), \displaystyle {h(x)=g(x)^{f(x)}} (and assuming that the first derivatives do exist for both functions) Next, notice that any attempts to differentiate h(x) by making use of the conventional rules of differentiati... WebIt's unfortunate that "secant" and "tangent" serve double purposes in mathematics, but we're stuck with them now. This isn't really a calculus matter, it's trigonometry. There's a neat …

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WebThe easiest way to do this is to start with the Pythagorean identity, solve for the sine in terms of cosine and replace each cosine with 1 over its reciprocal (which is secant): The radical … dono objetivo

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WebAdd a comment. 2. There is the expression. sec z = 1 + z 2 2 + 5 z 4 24 + ⋯ + ( − 1) n E 2 n ( 2 n)! z 2 n + ⋯. for the Taylor series, where E 2 n is an Euler number; see Abramowitz and Stegun, {\sl Handbook of Mathematical Functions}, p.~75, Equation 4.3.69; and the discussion of Euler numbers on pp.~804--805, and the table of values for ... http://math2.org/math/integrals/more/sec.htm WebJan 21, 2024 · This rule is used to find the derivative of a quotient function which says that. ( f g) ′ = g f ′ − f g ′ g 2, where ′ denotes the first order derivative. Let us express secx as a quotient function as follows. sec x = 1 cos x. Applying the above quotient rule of derivatives with f=1 and g=cosx, we get that. ( sec x) ′ = cos x ⋅ 1 ... don oozma kappa